# Mei C3 Numerical Methods Coursework

But does everyone benefit from our monetary system? It will be assumed that the reader has studied these preceding posts (10 minutes’ fascinating reading!

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I am going to use three different methods to solve different equations.

First of all, one root should be found successfully by using three different methods.

When taking square roots of both sides of an equation, one should be careful not to turf out the negative result without first considering whether it has a true meaning. In Part I we calculated the probability of winning a single-suit version of the Higher of Lower card game.

When using Pythagoras’ Theorem, the last step is to take square roots. The objective of this post is to find the probability of winning the full, unsimplified, 4-suit version of the game played in pubs across the land. I was recently roped into joining some friends for a pub quiz. For a start, I don’t watch soaps or football or take any interest in divorcing celebrities. I didn’t know, but I was alarmed and it was my duty to discover the probability of winning this game. I want to talk to you today about our monetary system.

Imagine a straight line (or “traversal”) connecting two opposite vertices of the cuboid 3. Note: Cubes are only counted if the traversal passes Note: If your diagonal goes exactly through a point, like in the 2×4 example, then it is not considered to pass through either of the diagonally adjacent squares.

The sum total of my contribution is usually a question about the periodic table and another about some obscure ’90’s one-hit wonder. Two players failed in succession and then the host declared that the contents of the pot would roll over to next week. Most, perhaps all, of us here at Forest School have benefited from the monetary system.You can tell if a function converges by the fact that the outputs become closer and closer to each other, if this does not happen then the function diverges and there is no value.The output of an iterative formula is written as: to the required number of decimal places.Since x appears twice in the equation, the problem cannot be solved algebraically.In the sense that there are equations which cannot be integrated and require numerical methods to approximate the answer, eg the midpoint rule.If we look back we found out there were problems with the formulas themselves however that was merely for the purpose of finding the best method, this cannot be used as a limitation because it doesn’t apply to this equation. Notice the =0 part, if this approximation is valid then by using our approximation (x) in this equation we should end up with an answer close to 0. Notice the degree of the polynomial is a high minus number meaning this number is tiny and extremely close to 0. In order to improve on this approximation we could find the root to more D. However earlier I did mention that excel is accurate to 15 D. P, this is definitely a limitation, if I had more time I would change my figures and calculate it to 15 D. The secant method requires two approximations of the root in order to work.Fortunately we’ve been provided with two roots, 0 and π/2.We can now call x(0) as π/2 and x(1) as 0, we can then substitute these values into the following equation. We can however lower the boundaries and thereby create a better approximation of the root.In order to lower the boundaries we merely continue reducing/increasing them until we hit the boundary of sign changes.

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